Comments on: Introductory talk on Geometric Algebra

By: Scott

Scott — Tue, 09 Feb 2010 03:08:29 +0000

Ah, missed that. Thanks again.

By: jmbr

jmbr — Mon, 08 Feb 2010 22:02:03 +0000

Hi Scott,

This is not a mistake, definitions (5) and (6) agree (note that B = b^c) with their general form which is given in (22) and (23).

Thanks again for working through the slides.

By: Scott

Scott — Mon, 08 Feb 2010 21:18:22 +0000

Sorry, I couldn’t edit the last slide. There is another slight mistake on slide 61. The definitions for (5) and (6) should be switched. This leads to a problem in the later computation, though.

By: jmbr

jmbr — Mon, 08 Feb 2010 19:26:59 +0000

Indeed, it should read a^(-b) = (-b)^(-a). Thank you for spotting that and taking the time to review the presentation. I will update the document soon.

By: Scott

Scott — Mon, 08 Feb 2010 15:38:16 +0000

There is a mistake on slide 38.

(a)^(-b) is not equal to (-a)^(-b)

Still, good job on this introduction, it gives a nice feeling for what is happening. I think it would be nice if there was more exposition on what you actually mean by ‘sweeping’ along another vector. I personally know what it is, but the idea was very foreign to me and painful at first. A bank of animations would clear that right up, along with all of the properties (like anti-commutivity).

Thanks again.

By: jmbr

jmbr — Mon, 08 Feb 2010 14:27:24 +0000

Thanks for posting it and notifying me. I wasn’t aware of this group.

By: Peeter Joot

Peeter Joot — Mon, 08 Feb 2010 13:57:48 +0000

fyi. I’ve posted a link to this in the google GA forum.

http://groups.google.ca/group/geometric_algebra/browse_thread/thread/64c72da3309663a0